Will choose brainliest (:
is the given linear expression a factor of the polynomial? show your work.
h(x)=x^4-4x^3-15x^2+58x-40; x-5
! (:

  yes

Step-by-step explanation:

There are several ways to go at this.

My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.

Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.

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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.

  (((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0

The value of h(5) is zero, so x-5 is a factor of h(x).

what graph

step-by-step explanation:

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24