Ineed an answer and explanation ? very much appreciated! < 3

Step-by-step explanation:

You need to know angles like PQT and the one labeled 148 equal 180, since putting them together makes a straight line and the relationship between "alternate exterior" and "alternate interior" angles.  Basically they are the same

If you need a more in depth explanation on those angles let me know.

ANyway, we'll start with what I mentions at first;

PQT = 180 - 148 = 32

Then PQT and SRT are alternate  interior angles so they are equal

RST = 180 - 104 = 76

then RST and TPQ are also alternate interior angles so both equal 76

Now, the sum of angles in a triangle are 180 so TPQ + PQT + QTP = 180 and RST + SRT + RTS = 180.  Plugging in what we know gets us RTS = 180 - 108 = 72 = QTP.

You might be wondering how this helps, well, RTQ is a straight line, so PTR + QTP = 180.  So that means PTR = 180 - QTP = 180 - 72 = 108

Let me know if something here doesn't make sense.  

the distance between point a and point b is 6 units

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.