Represent the given condition using a single variable, x.
the length and width of a rectangle whose length is 15 centimeters more than its width.
the width of the rectangle is

The width of the rectangle is x - 15

Step-by-step explanation:

Lets explain how to solve the problem

- The dimensions of the rectangle are length and width

- There is a relation between the length and the width

- The length of the rectangle is 15 centimeters more than its width

- More than means the length is larger than the width by 15 centimeters

 or the width is shorter than the length by 15 centimeters

Assume that the length of the rectangle is x

∵ The length of the rectangle = x

∵ The length of the rectangle is 15 centimeters more than the width

That means the width is less than the length by 15 centimeters, then to

get the width subtract 15 from the length

∴ The width of the rectangle = x - 15

The width of the rectangle is x - 15

y = 0.77(x)

step-by-step explanation:

the jacket retains this value after 23% cut or retains 77% of original value. plug original 87 jacket price for x and the remaining value should be y.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b