Pls this is due in 3 hours pls i beg of you pls show your work
solve each given equation and show your work. tell whether it has one solution, an infinite number of solutions, or no solutions, and identify each equation a contradiction, or neither.
(a) 6x + 4x - 6 = 24 + 9x
(b) 25 - 4x - 15 - 3x + 10 - x
(c) 4 x + 8 - 2x + 7 + 2x - 20

(A)6x+4x-6=24+9x

10x-6=24+9x

10x-9x=24+6

x=30.     (only 1 solution)

(B)25-4x = 15-3x+10-x

25-4x = 5-4x

25-5 = 4x-4x

30 = 0        (No solution)

(C)4x+8 = 2x+7+2x-20

 4x+8 = 4x -13

 4x-4x = -13-8

 0 = -21       (No solution)

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,