Acylindrical tank with a cross-sectional area of 100cm^2 is filled to a depth of 100 cm with water. at t=0, a drain in the bottom of the tank with an area of 10cm^2 is opened allowing water to flow out of the tank. the depth of water in the tank at time t\geq 0 is (t)=(10-2.2t)^2 . (5 pts.)
(a) check that d (0)=100, as specified.
(b) what is an appropriate domain for d?
(c) at what time is the tank first empty?

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

answer:

125 yards

explanation:

75+50=125. that is my answer

80 the answer is 80

step-by-step explanation: