Asequence is defined recursively using the equation . if f(1)=100, what is f(6)?

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The complete question is:

A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100, what is f(6) ?

Since, A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100,we have to find the value of f(6).

Consider

f(n+1) = f(n)-8

Let n =1, we get

f(1+1) = f(2) = f(1) - 8 = 100-8 = 92

Let n =2, we get

f(2+1) = f(3) = f(2) - 8 = 92-8 = 84

Let n =3, we get

f(3+1) = f(4) = f(3)-8 = 84 - 8 = 76

Let n =4, we get

f(4+1) = f(5) = f(4)-8 = 76 - 8 = 68

Let n =5, we get

f(5+1) = f(6) = f(5) - 8 = 68-8 = 60

Therefore, the value of f(6) is 60.

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