Agrocer want to mix two kinds of coffee. one kind sells for $1.15 per pound, and the other sell for $1.40 per pound. he wants to mix a total of 30 pounds and sell for $1.35 per pound. how many pounds of each kind should he use in the new mix? rozier want to mix two kinds of coffee. one kind sell for $1.15 per pound, and the other sell for $1.40 per pound. he wants to mix a total of 30 pounds and sell for $1.35 per pound. how many pounds of each kind should he use in the new mix

24 pounds of 1.35 and 6 pounds of 1.15

Step-by-step explanation:

First you need to be able to write equations:

x: pounds of 1.40 coffee in the mix

y: pounds of 1.15 coffee in the mix

He wants to mix 30 pounds:

x+y= 30

Also the new price will be 1.35:

1.40*x + 1.15*y = 1.35

Replacing y = 30 - x

1.40*x + 1.15(30-x) = 1.35

Solving that you get:

x = 24

y = 6

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

c is the correct answer

step-by-step explanation: