Given m∠lon=77∘\qquad m \angle lon = 77^\circ m∠lon=77 ∘ space, m, angle, l, o, n, equals, 77, degree m∠lom=9x+44∘\qquad m \angle lom = 9x + 44^\circ m∠lom=9x+44 ∘ space, m, angle, l, o, m, equals, 9, x, plus, 44, degree m∠mon=6x+3∘\qquad m \angle mon = 6x + 3^\circ m∠mon=6x+3 ∘ space, m, angle, m, o, n, equals, 6, x, plus, 3, degree find m∠monm\angle mon m∠mon m, angle, m, o, n :

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

i dont understand

step-by-step explanation:

the answer is 18 units because there are 18 small cubes inside the rectangle

hope this and p.s i am also in k12

step-by-step explanation: