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solve for c. a(c−b)=d c=d + aba c=d − abb c=d − aba c=ab − da

c = \frac {d + ab} {a}

Step-by-step explanation:

For this case we have the following equation:

a (c - b) = d

We want to solve the equation for the letter c.

To do this, we apply the distributive property:

ac-ab = d

Then, applying addition property of equality we have:

ac = d + ab

Then applying division property of equality we have:

c = \frac {d + ab} {a}

c

step-by-step explanation:

i think because what else can be a sample of every member

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)