One-fourth of the residents of a particular community leave their garage doors unlocked when they go out to do an errand. the local chief of police estimates that 5 percent of the garages with the doors unlocked will have something stolen, but only 1 percent of those locked will have something stolen. what is the probability if a garage is selected at random it will be unlocked? express your answer as a decimal carried out two places, e. g .10.

Required Probability = 0.625

Step-by-step explanation:

Given,

Probability of unlocked doors, P(U) = 0.25

Probability of locked doors, P(U') = 0.75

Probability of something being stolen when door is unlocked, P(S/U) = 0.05

Probability of something not being stolen when door is unlocked, P(S'/U) = 0.95

Probability of something being stolen when door is locked, P(S/U') = 0.01

Probability of something not being stolen when door is locked, P(S'/U') = 0.99\

probability of being stolen either door is locked or not,

P(S) =P(S/U).P(U) + P(S\U').P(U')

       = 0.05 x 0.25 + 0.95 x 0.75

       = 0.0125 + 0.0075

       = 0.02

Probability that door was unlocked when while steeling can by given by

            = 0.625

hence, the required probability is 0.625.  

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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