Ineed ! don't solve work me through how to do this!
q: josiah had three less than twice as many nickels as dimes. if the total value of his coins was $1.45, how many of each kind of coin did he have?
this is for me to write and solve the equation that it is looking for!
78 !

13 nickels and 8 dimes

Step-by-step explanation:

okay, we know that he has $1.45

we know $1= 100 cents.

so we know he has 145 cents

we know one nickel= $0.05

we know one dime=$0.10

we know he has twice as many minuses 3 nickels compared to dimes.

with this information we can make an equation d=dimes n= nickels

145= (5x(n-3)) + (10xd)

we know whatever we plug in for n, d will be half as much. so plug in even numbers that can easily be decided by 2 for n. then take whatever number you put for n and divide it by 2 to get d. for example, if you put 10 for n you would put 5 for d.

eventually you'll end up with an equation that looks like this

145=(5×(16-3))-(10×8)

meaning you have

16-3= 13 nickels

and. 8 dimes