(6x - 3)= (4x + 33).
what is the value of x?

Step-by-step explanation:

(6x-3)=(4x+33)

Combine like terms,

Subtract 4x on both sides and add 3 to both sides

2x=36

Divide by 2 on both sides

X=18

In order to solve for x, we can do the following:

6x - 3 = 4x + 33

6x - 3 + 3 = 4x + 33 + 3 (Add 3 to both sides)

6x = 4x + 36 (-3 + 3 = 0; 33 + 3 = 36)

6x - 4x = 4x + 36 - 4x (Subtract 4x from both sides)

2x = 36 (6x - 4x = 2x; 4x - 4x = 0)

2x/2 = 36/2 (Divide both sides by 2)

x = 18 (2x/2 = x; 36/2 = 18)

Thus, the value of x is 18.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

step-by-step explanation: