Consider the quadratic function f(x) = 4x^2 - 1. its vertex is preview the x value of its largest x-intercept is x = the y value of the y-intercept is y = preview preview preview

Its vertex is .

The x value of its largest x-intercept is .

The y value of the y-intercept is .

Step-by-step explanation:

A quadratic function in the format:

Has the vertex given by:

So

, we have that:

So

Its vertex is

The x-intercept values are the values of x when f(x) = 0;

So

The x value of its largest x-intercept is .

The y-intercept is the value of f(x) when x = 0, so,  f(0)

The y value of the y-intercept is .

300

step-by-step explanation:

28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.