The heights of adult women are approximately normally distributed about a mean of 65 inches, with a standard deviation of 2 inches. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to: a) 60 b) 62 c) 69 d) 70e) 74

Her height, in inches, is closest to 70.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean and standard deviation , the z-score of a value X is given by:

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

In this problem, we have that:

A z-score of 2.33 has a p-value of 0.9901. This means that a height with a z-score of 2.33 is in the 99th percentile.

So, what is the value of X when

Her height, in inches, is closest to 70.

where's the diagrams?