The age of jane is 80% of the age of alice. if we add both ages the result is 45. find the age of jane and alice

Age of Alice = 25, Age of Jane = 20.

Step-by-step explanation:

Let age of Alice = x

Then age of Jane is 80% of the age of Alice

=> Age of Jane = 80% of x = 80/100 * x = 0.8x

Adding the two ages gives 45.

The two ages are x and 0.8x.

The sum of the two ages is x+ 0.8 x = (1+0.8)x = 1.8x.

=> 1.8 x = 45

Dividing both sides by 1.8, x = 45/1.8

=> x= 25

But x represents the age of Alice.

So age of Alice is 25.

Age of Jane = 0.8* 25 = 20

Verification: Adding the two ages gives 45.

step-by-step explanation:

my butt

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it