Hi there!
i am having trouble solving these two questions and was wondering if someone could me out/explain how i have to slove it! the questions are in these images since i'm not too sure how to write them.

ok for number 1 its :  ∠2 = 49

for number 2 :  x =  19

Step-by-step explanation:

The way to start this question is by finding key elements.

It says a linear pair. Well, linear pairs are 2 angles thats degrees equal 180.

So i drew out a linear pair and put in the two equations from the angles

It doesn’t matter which side you put it on because it will equal 180.

So what we want to do first is find x.

This is so we can find what angle 2 equals.

Step 1. Soooo the first thing we do is make all the equations equal 180 because a linear pair is 2 angles (which are the ones that were given) equal 180. So we are making it equal to 180.

Step 2. So what we have is 5x + 6 + 2x - 1 = 180

Step 3. So then we combine like terms. This means to add, subtract, multiply, or divide any number that has the same exponent variables or just a number together. (there are more rules about this but its not needed right now.)

Step 4. So what we have now is 7x + 5 = 180 this is because we added 6 and -1 which is 5. Then we added 5x and 2x which is 7x

Step 5. We still want x by itself so we subtract 5 from itself and 180 to get rid of it. That gives us 7x = 175

Step 6. To get rid of the 7 so we have x by itself we divide 7 with itself and with 180 to get rid of it. Luckily for us, it evenly divides. So now we have x = 25

Step 7. But wait we are not done yet the question asks us what does angle 2 equals. Well all we have to do is plug in x in the angle 2 equation

Step 8. So we have 2x - 1 and we convert it 2  25 - 1

This is because we replaced x with what x equals.

Step 9. So 2   25 is 50 then we subtract 1 to it and now we are left with  2 = 49

If you need an explanation for question two you can ask for it.

If you confused with anything here I labeled each step so you can ask where you're confused.

stops on an even number.