For a certain event, 817 tickets were sold, for a total of $1919. if students paid $2 per ticket and nonstudents paid $3 per ticket, how many student tickets were sold?

532 student tickets were sold

Step-by-step explanation:

Let x be the no. of student's tickets sold

Let y be the no. of non student's tickets sold

We are given that 817 tickets were sold in total

So,  --1

Cost of 1 student's ticket = $2

So, Cost of x student's ticket = 2x

Cost of 1 non - student's ticket = $3

Cost of y non - student's ticket = 3y

We are given that  817 tickets were sold, for a total of $1919

So,  ---2

Solving 1 and 2

Substitute the value of y from 1 in 2

Substitute the value of x in 1

Hence 532 student tickets were sold

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

jml angle lkj & angle mj = lm