Show that a sequence {sn} coverages to a limit l if and only if the sequence {sn-l} coverages to zero.

Let be a sequence that converges to . This means for any , there is some such that for all . From this inequality we see that , so it follows that .

On the other hand, let be a sequence that converges to 0. This means for all large enough , and we get the simpler inequality for free, , so it follows that .

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg