Your team is in charge of game at cpm amusement park. one of the games involves a robotic arm that randomly grabs a stuffed animal out of a large bin. you need to set up the game so that the probability of a customer's grabbing a teddy bear is exactly 1/2
a. how would you set up the bin? explain
b. what if you returned to check on the bin and found that there were 4 teddy bears left and 12 other animals? what could you add to or remove from the bin to return the probability of selecting a teddy bear to 1/2?

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

a) at most means it can cost $12 or less

so the inequality sign would be ≤

you would then need to multiply the number of toppings by the 0.35 for each one and add it to the cost of the cheese pizza.

the equation would be 9.99 + 0.35x ≤ 12

b) using the above equation:

9.99 + 0.35x ≤ 12

subtract 9.99 from each side:

0.35x ≤2.01

divide both sides by 0.35:

x ≤ 2.01 / 0.35

x ≤5.74

at most you could have 5 toppings.

the 5 topping pizza would cost: 0.35 x 5 = 1.75 + 9.99 = $11.74