Q.2
the x coordinate of a point p is twice its y-coordinate. if p is equidistant
from q (2,-5) and r (-3, 6) find the coordinates of p.
q.3
find the ratio in which y axis divides the line segment joining the points
a (5.-6) and b (-1,-4). also find the coordinates of the point of division.
q.4
find the ratio in which the point(-3, k) divides the line segment joining
the points (-5,-4) and (-2,3). also find the value of k.
find the ratio in which pſ4, m) divides the line segment joining the
q.5
pointsa (2,3) and b(6,-3)hence find m.

Q2. (16,8)

Q3. , ratio=5:1

Q4. Ratio=2:1

Q5. Ratio=1:1

Step-by-step explanation:

Q2. Let (2a,a) be the coordinates of P.

Since P is equidistant  from Q (2,-5) and R (-3, 6), we have

This gives us:

Expand:

The coordinates of P are

Q.3  The equation of the line segment joining the points

A (5.-6) and B (-1,-4) is .

The x-coordinate of the point that divides AB in the ratio m:n is

The y-axis meets this line at

We substitute into this equation and solve for m and n.

Therefore the ratio is m:n=5:1

Q.4 The equation of the line segment joining

the points (-5,-4) and (-2,3) is .

The point (-3, k) must satisfy this line because it lies on it.

.

We again use the equation to find the given ratio.

Substitute:

The ratio is m:n=2:1

Q. 5 The equation of the line joining A (2,3) and B(6,-3) is .

We substitute (4,m) to get:

12+4m=12

4m=0

m=0

It is obvious that: (4,0) is the midpoint of A(2,3) and B(6,-3).

Hence the ratio is 1:1

2x^2+5x+17

your welcome. : )

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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