Factor. 25m100−121n16 (5m50−11n8)(5m50+11n8) (5m50−11n8)2 (5m10−11n4)2 (5m10−11n4)(5m10+11n4)

The answer to your question is (5m50−11n8)(5m50+11n8)

Step-by-step explanation:

                                             25m¹⁰⁰−121n¹⁶

find the prime factors of 25 and 100

    25     5                                  121     11

       5     5                                   11      11

        1                                            1

25 = 5 x 5 = 5²                       121 = 11 x 11 = 11²

m¹⁰⁰ = (m⁵⁰)²                           n¹⁶ = (n⁸)²

Substitution

                     25m¹⁰⁰−121n¹⁶ = 5²(m⁵⁰)²   - 11² (n⁸)²

                                            = (5m⁵⁰  - 11n⁸)  (5m⁵⁰  + 11n⁸)

(5m50−11n8)(5m50+11n8)

(5m50−11n8)2

(5m10−11n4)2

(5m10−11n4)(5m10+11n4)

step-by-step explanation:

ask goog great chance of finding the solution there

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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