carla has $90. she makes $6 per day walking a
neighbor's dog for half an hour, but spends $7.50
per day on lunch. what is the fewest number of
days for which carla will have less than $30?

4 days less than 30$

step-by-step explanation

since carla has 90$ and makes 6$ per day you divide 90 by 6 that gets you 15.

so she worked 15 days.

then since she spends 7.50 subtract on lunch everyday subtract 7.50 from 30 and you will have to do that 4 times. so for 4 days she will have less than 30$

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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