First angle in the triangle is 52 degrees celsius and i need to find the outside and top

In figure,

AC = BC (given)

Since, in a triangle , angles opposite to equal sides are also equal.

Therefore,

b= 52°

Now,

°.° c is exterior angle of triangle.

.°. c = b + 52°

=> c = 52° + 52°

=> c = 104°

Solution:-

-------------

b = 52° & c =104°

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step-by-step explanation:

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for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c