Eureka math module 1
rum
lesson 10 - independent practice
jaguar's speed: tin
timsan
7001
5001
1. the graph to the right shows the relationship of the
amount of time (in seconds) to the distance (in feet) run
by a jaguar
distance in foot)
4001
3. the a
cost of
of how
a.
3001
6.2003
2001-
174)
1001
11,50)
10.05
time in seconds)
a. what does the point (5,290) represent in the context of the
it represents the distance covered
by jaguar in 5 sec.
does the point (3, 174) represent in the context of the situation?
what does the point (3,174 ) represent in the context of the situation

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

y=x+9

?

step-by-step explanation:

the radius is 2 times the diameter.

step-by-step explanation: