Write the equation of a line that is parallel to y=1/2x−4y and that passes through the point (9,−6)

the desired equation is

y = (1/2)x - 21/2

Step-by-step explanation:

Looks as tho' you may have typed in an extra 'y' here.  I will proceed under the assumption that you meant y = (1/2)x - 4.  This line has a slope of 1/2.

Any line parallel to it also has a slope of m = 1/2.

Start by replacing y, x, m and b in y = mx + b with the knowns:

y = mx + b becomes -6 = (1/2)(9) + b.

Clear this of fractions by multiplying all 3 terms by 2:

-12 = 9 + 2b, or:

-21 = 2b.  Dividing both sides by 2 results in b = -21/2.

Thus, the desired equation is

y = (1/2)x - 21/2

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

attachment?

step-by-step explanation: