the area of a certain rectangle is 288 yd2. the perimeter is 68 yd. what are the dimensions of the rectangle?
a) 24 yd by 10 yd
b) 18 yd by 16 yd
c) 22 yd by 12 yd
d) 36 yd by 8 yd
show work-thx

The rectangle is 16*18

Step-by-step explanation:

The area of a rectangle is length * width and the perimeter is 2 times length * width

A = l*w

P = 2(l+w)

Replacing A and P

288 = l*w

68 = 2(l+w) => 34 = l+w => 34 - w = l

replacing l in the area

288 = (34 - w) w

w^2 - 34w + 288 = 0

(w - 16)(w - 18)

w = 16

w = 18

replacing in 34 - w = l

you get that when w = 16, l = 18 and when w = 18, l = 16

huh? im pretty sure it is in 199

step-by-step explanation:

44

step-by-step explanation: