2. find the equation of a line that is parallel to the line y=-- x - 3 and goes through the point (-4,3).
what’s the answer?

Use the point-slope formula.

y - y_1 = m(x - x_1)

y - 3 = 1(x + 4)

y = x + 4 + 3

y = x + 7

Done.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: