Suppose you want to represent a triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet. how
long should the sides of the triangle be in inches?
the sides of the triangle on the drawing should be
a.) 6, 8 and 9
b.) 10.14 and 16
c.) 14. 18 and 20
d.)24.32 and 36

answer:   the sides of the triangle on the drawing should be 6 inches, 8 inches, and 9 inches.

step-by-step explanation:

given: a triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet.

then, 1 feet of original triangle =\frac{1}{2} inch on drawing.

now, the sides of the triangle on the drawing are: -

12 feet =\frac{1}{2}\times12=6\text{ inches}

12 feet =\frac{1}{2}\times16=8\text{ inches}

12 feet =\frac{1}{2}\times18=9\text{ inches}

hence, the sides of the triangle on the drawing should be 6 inches, 8 inches, and 9 inches.

true

explanation:

x/3-10=8

x/3=18

x=48