Arock is thrown at a window that is located 18.0 m above the ground. the rock is thrown at an angle of 40.0° above horizontal. the rock is thrown from a height of 2.00 m above the ground with a speed of 30.0 m/s and experiences no appreciable air resistance. if the rock strikes the window on its upward trajectory, from what horizontal distance from the window was it released?

27.32 m

Step-by-step explanation:

We are given that

Height of window from the ground=18 m

Height of rock  form the ground=2 m

Speed of thrown rock=30 m/s

We have to find the horizontal distance from the window from which rock was release.

Difference between window and rock=18-2=16 m

Initial vertical velocity component=m/s

Initial horizontal velocity component=

If the rock is reached to maximum height

Then, maximum height=

Time taken by rock to reach maximum height=

Distance between window and maximum height at which rock reached=18.9731-16=2.973 m

Time to drop 2.973 m=

Time to be at 16 m=1.96775-0.77893=1.189 s

Horizontal distance=

Hence, horizontal distance of rock from the window from which rock was released=27.32 m

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24/56=hx^7

step-by-step explanation: