Assume that in a particular military exercise involving two units, red and blue, thereis a 60 % chance that the red unit will successfully meet its objectives and a 70% chance that the blue unit will do so. there is an 18 % chance that only thered unit will be successful. what is the probability that both units will meet theirobjectives? what is the probability that one or the other but not both of the unitswill be successful?

a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

Hence, there are 88% chances that one or the other but not both of the units will be successful.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~