Mathematics, 24.09.2019 23:00 shaee7335
Solve for x: two thirds(x − 2) = 4x. x = negative two fifths x = negative five halves x = two fifths x = −2
Answers: 2
Mathematics, 21.06.2019 14:30
Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.
Answers: 3
Mathematics, 21.06.2019 15:30
Will give are given that xy is parallel to zw. if xz is a transversal that intercepts xy and zw, angle angle alternate interior angles. since xy is parallel to zw, we know that these angles are we also know that angle xvy and angle zvw are , and thus congruent. we can conclude that △xyv ~ △zwv using the similarity theorem.
Answers: 2
Mathematics, 21.06.2019 19:50
Table which ratio is equivalent to 3: 7? 6: 7 3: 21 24: 56 15: 30
Answers: 1
Solve for x: two thirds(x − 2) = 4x. x = negative two fifths x = negative five halves x = two fifth...
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