Given m< lom = 3x +38 m< mon= 9x+28 find m< lom:
me !

The answer to your question is: m∠LOM = 44°

Step-by-step explanation:

Data

m< LOM = 3x +38

m< MON= 9x+28

m< LOM = ?

Process

They are complementary angles

                    m∠LOM + m∠MON = 90°

                   3x + 38 + 9x + 28 = 90°

                   12x + 66 = 90°

                   12x = 90 - 66

                   12x = 24

                   x = 24/12

                   x = 2

m∠LOM = 3(2) + 38

             = 6 + 38

            = 44°

m∠ MON = 9(2) + 28

m∠MON = 18 + 28

m∠MON = 46°

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step-by-step explanation:

it would be 6xy and -16xy.