Find the function that is finally graphed after the following transformations are applied to the graph of y = square root x
the graph is shifted down 6 units, reflected about the x-axis, and finally shifted left 2 units.
x.

y=-(x+2)^2 -6

Step-by-step explanation:

y=a(x-h)^2 + 6

a=-1

h=-2

k=-6

The vertex of y=x^2 is on (0,0)

When you shift an equation down, and when you shift an equation left you are basically subtracting from the y and x components respectively, so:

(0-2,0-6) = (-2,-6) = (h,k)

Or, you can just remember that a positive k (or y) , is above the origin and a negative k is below the origin.

H (or x) is the opposite. Positive h is to the left and negative h is to the right.

Step-by-step explanation:

shift down 6 units down:

reflected about the x-axis:

shifted left 2 units:

Combine all three:

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24