Which simplifications of the powers of i are correct?
there is more than one correct answer. select all correct answers.
i5=i3⋅i2=−i⋅−1=i
i8=i4⋅i4=1⋅1=1
i8=i4⋅i4=−1⋅−1=1
i7=i4⋅i3=−1⋅−i=i
i7=i4⋅i3=1⋅−i=−i
i6=i4⋅i2=1⋅−1=−1
i5=i3⋅i2=i⋅−1=−i
i6=i4⋅i2=−1⋅−1=1

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

what’s the question?