16) kayla's school is selling tickets to the annual dance competition. on the first day of ticket sales
the school sold 6 adult tickets and 8 child tickets for a total of $98. the school took in $70 on the
second day by selling 2 adult tickets and 8 child tickets. find the price of an adult ticket and the
price of a child ticket.

The price of an adult ticket is $7 and the price of a child ticket is $7

Step-by-step explanation:

Let

x -----> the price of an adult ticket

y ----> the price of a child ticket

we know that

First day

-----> equation A

Second day

----> equation B

Subtract equation B from equation A and solve for x

Find the value of y

substitute the value of x

therefore

The price of an adult ticket is $7 and the price of a child ticket is $7

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204