Uppose that 61% of all adults in a certain community are obese and that 31% suffer from diabetes. if 23% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)? write your answer as a decimal (not as a percentage).

0.69

Step-by-step explanation:

A: obese

B: diabetes

P(A) = 61

P(B) = 31

P(A and B) = 23

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 61 + 31 - 23 = 69%=0.69

true

step-by-step explanation:

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step-by-step explanation: