While her kid brother is on a wooden horse at the edge of a merry-go-round, sheila rides her bicycle parallel to its edge. the wooden horses have a tangential speed of 6 m/s. sheila rides at 4 m/s. the radius of the merry-go-round is 8 m.. at what time intervals does sheila encounter her brother, if she rides in the direction of rotation of the merry-go-round?

25.12 seconds

As we have been given ion the question,

Tangential speed of her brother at the Wooden Horse = 6 m/s

Tangential speed of Sheila = 4 m/s

Radius of merry go round, r = 8 m

Now,

We know that,

v = r.ω

So,

Angular velocity of brother is given by,

And,

Angular velocity of Sheila is given by,

Relative Angular Velocity = 0.75 - 0.5 = 0.25 rad/s.

Therefore, the time taken by Sheila to encounter her brother again is given by,

Therefore, Time Taken to encounter again is 25.12 seconds.

(2,9)

i think thats the answer i checked it on google