Determine the area under the standard normal curve that lies to the left of (a) z equals negative 1.53 commaz=−1.53, (b) z equals negative 1.51z=−1.51, (c) z equals negative 0.87z=−0.87, and (d) z equals negative 0.63z=−0.63. (a) the area to the left of zequals=negative 1.53−1.53 is nothing. (round to four decimal places as needed.)

(a) z = -1.53 --> P(x<z) = 0.0630

(b) z = -1.151 --> P(x<z) = 0,0655

(c) z = -0.63 --> P(x<z) = 0,2643

Step-by-step explanation:

To know the area that lies to the left, equal to P(x<z), the best way is to look at tables of standard normal curve.

(a) z = -1.53 --> P(x<z) = 0.0630

(b) z = -1.151 --> P(x<z) = 0,0655

(c) z = -0.63 --> P(x<z) = 0,2643

b.my answer is b.

brainliest

the anwser is d) 75°

step-by-step explanation: