If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? use the equation h = −16t2 + 4t + 4. round your answer to the nearest hundredth.

0.64 seconds

Step-by-step explanation:

In the equation provided:

h = −16t2 + 4t + 4

h is the height of the ball and t is time. Since we want to find the time when the ball touches the floor, then height is 0. This leaves us with the equation

-16 + 4t + 4 = 0

This is a quadratic equation can be solved with the following formula:

where a=-16

b=4

c=4

Solving for t we will find two different results:

Since time can't be negative, we discard t2 and choose t1.

Since it is required to answer in the nearest hundredth, we round the result to t=0.64 seconds.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1