Can the absolute value of an inequality be more than a negative?
example:
4 |x-6| ≥ -8

Yes, it would be all real numbers. If a negative was more than the absolute vaule, it would be false

Step-by-step explanation:

|x-6|>-2

pos. neg.

The the absolute vaule is ALWAYS positive so like I said before if the sign was facing towards the -2 it would be false

4 |x-6| (greater than or equal to)> -8

First you have to divide 4 on both sides since its outside the absolute vaule

then you will be left with

|x-6|>-2

since the 2 is a negative, you may think that this is automatically no solution, but sadly it isn't.

since the sign says the pos. sign is greater the equation is true and "all real numbers"

hope that helps!!

the answer to question 1 is -8, 28.

step-by-step explanation: