The fraction of defective integrated circuits produced in a photolithography process is being studied. a random sample of 300 circuits is tested, revealing 14 defectives. calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool. round the answers to 4 decimal places.

Step-by-step explanation:

Given : Sample size : n= 300

The sample proportion of defectives :

Significance level for 95% confidence level =

Critical z-value:

Confidence interval for population proportion :

Hence, a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool=

answer:

step-by-step explanation:

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3