Hey everyone !

a triangle has sides measuring 14 cm, 10 cm and 6 cm. the measure of the largest angle of this triangle measures:
note: perimeter = 30

you.

The measure of the largest angle is 120°

Step-by-step explanation:

Lets explain how to find the measure of an angle from the length of the

sides of the triangle

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

 to angle A is BC , the side opposite to angle B is AC and the side

 opposite to angle C is AB, So to find measure of angle A use the rule

Lets solve the problem

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

 AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴

∴

∴

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C =

* The measure of the largest angle is 120°

answer:      

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: