Arectangular lot is 50 yards wide and 90 yards long. give the length and width of another rectangular lot that has the same perimeter but a smaller area.

Length and width of another rectangular lot that has the same perimeter but a smaller area is found out

             Length = 95 feet

             Width = 45 feet

Step-by-step explanation:

A rectangular lot is 50 yards wide and 90 yards long.

Perimeter = 2 x (length + breadth) = 2 x ( 90 + 50) = 280 feet

Area = length x breadth = 90 x 50 = 4500 ft²

Here we need to find length and width of another rectangular lot that has the same perimeter but a smaller area.

So perimeter of new rectangle = 280 feet

         2 x (length + breadth) = 280

           length + breadth = 140

 Assume length = 95 feet , so width = 140 - 95 = 45 feet

Area = 95 x 45 =4275 ft²

Here area is less than 4500 ft².

Length and width of another rectangular lot that has the same perimeter but a smaller area is found out

             Length = 95 feet

             Width = 45 feet

answer: 32.68

step-by-step explanation:

x=2

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: