Use a proof by contradiction to prove that the sum of two odd integers is even.

Step-by-step explanation:

to prove that the sum of two odd integers is even.

Let a and b be two odd integers.

If possible assume that

, i.e. sum is a product of 2, hence even.

Since a is odd,

for some integer k.

Subtract a from a+b to get

i.e. b is a multiple of some integer l by 2

i.e. b is even.

This contradicts our assumption that both a and b are odd

Hence proved that the sum of two odd integers is even.

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

a - base

b - exponent

so,