Find the distance between line 11x-60y-15=0 and point (2, 1/60)

The answer to your question is: d = 6 / 61 or 0.1 units

Step-by-step explanation:

Data

Line: 11x - 60y - 15 = 0   A = 11; B = -60; C = -15

Point (2, 1/60)                 x = 2    y = 1/60

Formula

d = | Ax + By + C | / √(A² + B²)

Process

d = | (11)(2) + (-60)(1/60) -15 | / √(11² + (-60²)

d = | 22 -1 - 15 | / √ 121 + 3600

d = | 6 | / √3721

d = | 6 | / 61

d = 6 / 61 or 0.1 units

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.