Two consecutive integers are such that their sum is greater than 98 decreased by twice the larger. find the smallest possible values for both integers.

answer:

24 and 26

step-by-step explanation:

x = smaller

x+2 = larger

their sum, x+(x+2), is greater than, > , 98 decreased by, -, twice the

larger, 2(x+2).

so:

x+(x+2) > 98-2(x+2)

  x+x+2 > 98-2x-4

  2x+2 > 94-2x

  2x+2x > 94-2

    4x > 92

      x > 23

since x is the smaller, it must be greater than 23,

and the larger, x+2, must be 25 or larger.

the smallest two such consecutive even integers are 24 and 26.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.