Need asap due tommrow

alberto uses geometry software to draw
astu and point p, as shown. he marks
pas a center and uses the software to
rotate astu 115° around point p.
he labels the image of astu as as't'u'.
42
which three angles must have the same measure? what is the measure of these angles?

The three internal angles of the triangle S'T'U' must have the same dimensions as the three internal angles of triangle STU.

Step-by-step explanation:

Due to the fact that Alberto is using a simple rotation around point P, and no any extension or contraction, all three vertices of the original triangle are rotated the same angle of 115 degrees, and should keep the relative distance among them intact, therefore keeping the internal angles at the same value they were in triangle STU.

The measure of those angles should therefore be:

Angle S'T'U' = angle STU

Angle T'U'S' = angle TUS

Angle U'S'T' = angle UST

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dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3