Acash register contains $10 bills and $20 bills with a total value of $340. if there are 23 bills total then how many of each does the register contain?

So there are 12 bills of $10 and 11 bills of $20.

Step-by-step explanation:We are given that the cash register contains $10 and $20 bills.

Let us say there are x number of $10 bills and y number of $20 bills.

So there are total 23 bills.

(1)

(2)

We are also given that the total value of bills is $340 .

So that gives us the second equation,

(3)

Plugging the value of x from equation (2) in (3),

y=11

Plugging this value of y back in equation (2),

x=23-11= 12

12 bills of $10 and 11 bills of $20.

because 12*10= 120 and 11*20= 220

add 120+220=340

have a good day