The normal time to perform a repetitive manual assembly task is 4.25 min. in addition, an irregular work element whose normal time is 1.75 min must be performed every 8 cycles. two work units are produced each cycle. the pfd allowance factor is 16%. determine the anticipated amount of time worked per 8-hour shift that corresponds to the pfd allowance factor of 16%.

76.8 minutes

Step-by-step explanation:

Every 8 cycles we have 6 regular work elements plus 1 irregular work element.  

So, the normal time for 8 cycles is  

3*4.25+1.75 = 14.5 minutes.

Since the PDF allowance factor is 16%, the standard time for 8 cycles is 14.5 increased 16%

14.5*1.16 = 16.82 minutes.

So, the anticipated amount of time worked every 14.5 minutes

is 2.32 minutes.

An 8-hour shift has 480 minutes = 33.1034*14.5, so  the anticipated amount of time per 8-hour shift is

33.1034*2.32 = 76.8 minutes

i don’t see a picture

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.