Multiple-choice questions each have 6 possible answers, one of which is correct. assume that you guess the answers to 4 such questions. use the multiplication rule to find the probability that the first three guesses are wrong and the fourth is correct. that is, find p ( w w w c ) , where c denotes a correct answer and w denotes a wrong answer.

5/1296

Step-by-step explanation:

P(correct) = 1/6

P(Wrong)= 5/6

Assume that you guess the answers to 4 such questions.

all events are independent to each other

here W= wrong and C= correct

So,P(WWWC)= P(W)*P(W)*P(W)*P(C)

= 1/6*1/6*1/6*5/6= 5/1296

So, the probability that the first three guesses are wrong and the fourth is correct. = 5/1296

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

h/o/e/s mad

step-by-step explanation:

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